Answer:
Lewis structure attached below
Explanation:
Let's use the standard steps of drawing a Lewis structure for any compound in this problem:
- calculate the total number of valence electrons: hydrogen is in group 1A, it contributes 1 valence electron, bromine is in group 7A, so it has 7 valence electrons. The total number of valence electrons is, therefore, 8;
- assign the central atom, in this case, we don't have any, as it's a diatomic molecule;
- make single bonds between terminal atoms and central atom, in this case, we make a single bond to hydrogen, as it can have a maximum of one bond (2 electrons);
- assign the remaining electrons (8 - 2 = 6) as lone pairs on a central atom: this provides 3 lone pairs for bromine, in this case, it also has an octet, so we have a Lewis structure.
This Lewis structure contains 3 lone pairs on bromine and a single bond between H and Br. Image attached below.
