Answer:
ratio of the average convection heat transfer = 2
Explanation:
local heat transfer expression can be written as
[tex]H_{x}=Cx^{0.5}[/tex] (1)
C= Constant
x=measured from the leading edge of the plate
We need to find local heat transfer coefficient at
x=5L
so for equation 1 it can be written as
[tex]H_{x=5L}=C5L^{0.5}[/tex]
we can find the average heat transfer over entire lenght of plate as
[tex]H=\frac{1}{5L}\int\limits^5_0 {h_{x} } \, dx[/tex] (2)
subsitute [tex]H_{x=5L}=C5L^{0.5}[/tex] in equation 2
[tex]H=\frac{C}{5L}\int\limits^5_0 {x^{-0.5} } \, dx[/tex]
[tex]H=\frac{10C}{L}L^{-0.5}[/tex]
[tex]h=10CL^{-0.5}[/tex]
for ratio of the average convection heat transfer coefficient over the entire plate of length L to the local convection heat transfer coefficient at the end of the plate is given as
[tex]ratio = \frac{H}{H_{x} }[/tex]
Now putting values for H ,Hx and 5L for x
[tex]r=\frac{10CL^{-0.5}}{5CL^{-0.5} }[/tex]
[tex]r=2[/tex]