Answer:
Step-by-step explanation:
Given that many couples believe that it is getting too expensive to host an "average" wedding in the United States.
Population mean =24066
Sample mean = 23224
Sample size = 40
Sample std dev = 2903
Since sample std dev is known, we use t critical value.
df =39
Sample mean follows a normal distribution with mean = 23224, and std dev = [tex]\frac{s}{\sqrt{n} } \\=\frac{2903}{\sqrt{40} } \\=459.005[/tex]
t critical value = 2.023
Margin of error = 2.023*459.005
Confidence interval[tex](22295.43, 24152.57)[/tex]