Question

What is the equation the line that passes through the points (2,4) and (4,0)

Answer 1

Answer:

The equation of the line is 2 x + y = 8.

Step-by-step explanation:

Here the given points are ( 2, 4) & ( 4, 0)

Equation of a line whose points are given such that

( $x_{1}, y_{1}$) & ( $x_{2}, y_{2}$ )-

 y - $y_{1}$  =   $\frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }$ ( x - $x_{1}$ )

i.e.  y - 4 = $\frac{ 0 - 4}{ 4 - 2}$   ( x- 2)

    y - 4 =  $\frac{- 4}{2}$ ( x - 2 )

    y - 4 = - 2  ( x - 2 )

     y - 4 =  - 2 x + 4

    2 x + y = 8

Hence the equation of the required line whose passes trough the points ( 2, 4) & ( 4, 0)  is 2 x + y = 8.