Respuesta :
Answer:
4Q
Explanation:
Case 1 :
[tex]m[/tex] = mass of the metal
[tex]c[/tex] = specific heat of the metal
[tex]\Delta T[/tex] = Change in temperature = 7 - 4 = 3 C
Amount of heat required for the above change of temperature is given as
[tex]Q = m c \Delta T\\Q = m c (7 - 4)\\Q = 3 m c[/tex]
Case 2 :
[tex]m[/tex] = mass of the metal
[tex]c[/tex] = specific heat of the metal
[tex]\Delta T[/tex] = Change in temperature = 19 - 7 = 12 C
Amount of heat required for the above change of temperature is given as
[tex]Q' = m c \Delta T\\Q' = m c (12)\\Q' = (4)(3 m c)\\Q' = 4Q[/tex]
Hence the correct choice is
4Q
Answer:
So in order to increase the temperature of the material from 7° C to 19°C, heat required to the material is is 3 Q
Explanation:
We know temperature is directly proportional to amount of heat applied to the substance.
Q = mcdT
Q = heat supplied
m=mass of the substance
c= specific heat capacity
dT= increase in temperature
Let let us consider two situations as dQ_1 and dQ_2
Therefore,
[tex]\frac{Q_1}{Q_2}= \frac{dT_1}{dT_2}[/tex]
[tex]\frac{Q_1}{Q_2}= \frac{7-3}{19-7}[/tex]
[tex]\frac{Q_1}{Q_2}= \frac{4}{12}[/tex]
[tex]\frac{Q_1}{Q_2}= \frac{1}{3}[/tex]
Q1=Q
then, Q2 = 3Q
So in order to increase the temperature of the material from 7° C to 19°C, heat required to the material is is 3 Q