Answer:
There are 51 men in DOG.
Number of men who play baseball only are 2.
Number of men who play football and baseball but do not play basketball = 19
Step-by-step explanation:
We can see from the Venn diagram attached,
n(A∩B∩F) = 3
n(A∩B) = 6
n(B∩F) = 5
n(A∩F) = 7
n(A∪B∪F) = n(A) + n(B) + n(F) - [n(A∩B) + n(A∩F) n(B∩F)] + n(A∩B∩F) + n(N)
= 20 + 18 + 23 - (9 + 8 + 10) + 3 + 14
= 61 - 27 + 17
= 51
Therefore, there are 51 men in DOG.
Number of persons who play baseball only = n(A) - [n(A∩B) + n(A∩F)] + n(A∩B∩C)
= 20 - (6 + 7 + 3)
= 20 - 16
= 2
Therefore, number of men who play baseball only = 2
Number of men who play football and baseball but do not play basketball
= 8 + 5 + 6
= 19
Therefore, number of men who play football and baseball but do not play basketball = 19