Answer:
The time taken to move distance of 280 feet at the speed of 1.75 feet per second is 160 seconds
Step-by-step explanation:
Given as :
The speed of the moving walkway at an airport = s = 1.75 feet per second
The distance cover on the walkway = d = 280 feet
Let The time taken to move 280 feet = t sec
Now, According to question
Time = [tex]\dfrac{\textrm distance}{\textrm speed}[/tex]
t = [tex]\dfrac{\textrm d}{\textrm s}[/tex]
t = [tex]\dfrac{\textrm 280 feet}{\textrm 1.75 ft per sec}[/tex]
t = 160 seconds
So, The time taken to move distance of 280 feet at the speed of 1.75 feet per second = t = 160 seconds
Hence, The time taken to move distance of 280 feet at the speed of 1.75 feet per second is 160 seconds . Answer
