Respuesta :
Answer:
OPTION C
Step-by-step explanation:
The given polynomial is: 1280 x¹¹ - 405 x⁷.
The least power of the variable is taken common outside. So we get:
x⁷{1280 x⁴ - 405}
Now, 5 is a factor of both 1280 and 405.
So, it can be written as:
5x⁷{256x⁴ - 81}
We know that [tex]$ a^2 - b^2 = (a + b)(a - b) $[/tex]
Also, 256 = 16² and 81 = 9².
Therefore, this can be rewritten as: [tex]$ 5x^7 \{(16x^2)^2 - 9^2\} $[/tex]
Using the above formula, a = 16x² and b = 9.
Therefore, this becomes: [tex]$ 5x^7 \{ (16x^2 - 9) (16x^2 + 9)\} $[/tex]
[tex]$ (16x^2 - 9) $[/tex] can again be factorized with a = 16x and b = 3.
Therefore, it would be: [tex]$ 5x^7 \{ (4x + 3)(4x - 3) (16x^2 + 9)\} $[/tex]
Hence, OPTION C is the answer.
Answer:
Option C
Step-by-step explanation:
The given polynomial is: 1280 x¹¹ - 405 x⁷.
The least power of the variable is taken common outside. So we get:
x⁷{1280 x⁴ - 405}
Now, 5 is a factor of both 1280 and 405.
So, it can be written as:
5x⁷{256x⁴ - 81}
We know that
Also, 256 = 16² and 81 = 9².
Therefore, this can be rewritten as:
Using the above formula, a = 16x² and b = 9.
Therefore, this becomes:
can again be factorized with a = 16x and b = 3.
Therefore, it would be:
Hence, OPTION C is the answer.
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