Answer:
6 mg of the metal needs to be added.
Step-by-step explanation:
Let the amount (in mg) of metal that needs to be added by y.
Therefore, the amount of silver in the above metal is 0.04y.
Prior to mixing, 11 mg of a metal contained 38% of silver (Given).
Therefore, the amount of silver before= [tex]\frac{38}{100}*11[/tex]= 4.18 mg
The total amount of silver after mixing, 4.18 + 0.04y mg
The total amount of metal after mixing, 11 + y mg
New percentage of silver = 26% .
Thus, [tex]\frac{4.18+0.04y}{11+y}*100= 26[/tex]
[tex](4.18 +0.04 y) * 100 = 26 *(11 +y)[/tex]
[tex]418+4y=286+26y[/tex]
[tex]132=22y[/tex]
y=6 mg
Therefore, the amount of metal that needs to be added is 6 mg.
