1 moles of a gas are initially initially under pressure 4 × 105 Pa at T=300 K. In this problem, you will want to use the following relationships:Definition of Gibbs free energy: G=U−TS+PV Equipartition: U=NDOF2NkT+constEntropy of an ideal gas: S=NklnV+const Ideal gas law: pV=NkTEquation of state for system with excluded volume b: (V−Nb)p=NkT

1)If the gas is ideal, how much does G change when the gas is allowed to expand isothermally until the pressure is reduced to 2 × 105 Pa?

Answer = -1729

2)How much did the chemical potential, ??, change in part (1)? ?final-?initial= ?

3) Now assume the gas has no interaction energy but does have an excluded volume per particle, b=1.9 × 10-28 m3, which means that S = Nk ln(V-Nb) + f(T,N) , where f is some function you won't need to know since T and N don't change. How much does G change when the gas expands isothermally until the pressure is reduced from 4 × 105 Pa to 2 × 105Pa? Gfinal-Ginitial= ?

4) How much did the chemical potential change in the process of part (3)? ?final-?initial= ?

Respuesta :

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

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