There are 20 number of DVD's in Louis collection
Solution:
Let "J" be the number of DVD's with Jake
Let "B" be the number of DVD's with Bo
Let "L" be the number of DVD's with Louis
Given that Jake owns twice as many DVDs as Louis
So we can say,
number of DVD's with Jake = 2(number of DVD's with Loius)
J = 2L ------ eqn 1
Given that Bo has sixty fewer DVDs than five times Louis’s collection
So we can say,
number of DVD's with Bo = 5 times number of DVD's with Louis - 60
B = 5L - 60 ---- eqn 2
Given that Jake and Bo have the same amount of DVDs
number of DVD's with Jake = number of DVD's with Bo
J = B ---- eqn 3
Let us solve eqn 1, 2, 3 to find value of "L"
From eqn 1 and eqn 3,
2L = B ----- eqn 4
Substitute eqn 4 in eqn 2
2L = 5L - 60
2L - 5L = -60
-3L = -60
Thus there are 20 number of DVD's in Louis collection