Answer:
2491.24407 kg/m³
Explanation:
Weight of water displaced is given by
[tex]28.4-17=11.4\ N[/tex]
Mass of water displaced
[tex]\dfrac{11.4}{9.81}=1.16207\ kg[/tex]
Volume of water is given by
[tex]V=\dfrac{m}{\rho}\\\Rightarrow V=\dfrac{1.16207}{1000}\\\Rightarrow V=1.16207\times 10^{-3}\ m^3[/tex]
The volume of water displaced is the volume of the statue
Ceramic mass is
[tex]m_c=\dfrac{28.4}{9.81}=2.895\ kg[/tex]
Density will be
[tex]\rho_c=\dfrac{m_c}{V}\\\Rightarrow\rho_c=\dfrac{2.895}{1.16207\times 10^{-3}}\\\Rightarrow \rho_c=2491.24407\ kg/m^3[/tex]
The density of the ceramic is 2491.24407 kg/m³