Answer:
The final velocity of the ship is, v = 136050000 m/s
The total distance covered, s = 6.94 x 10¹⁷ m
Explanation:
Given data,
The constant acceleration of the space ship, a = 75 m/s²
The time period of the space ship acceleration is t = 3 weeks
t = 1.814 x 10⁶ s
The initial velocity of the ship is u = 0 m/s
The final velocity of the ship is,
v = u + at
= 0 + 75 (1.814 x 10⁶)
= 136050000 m/s
The distance space ship traveled, can be calculated from the second equation of motion.
s = ut + ½ at²
= 0 + ½ 75 (136050000)²
= 6.94 x 10¹⁷ m
Hence, the total distance covered, s = 6.94 x 10¹⁷ m
