A flight attendant pulls a suitcase 250.0 m along a level airport floor with a force of 30.0 n at an angle of 50.0 above the horizontal. How much force is done on the flight bag

Respuesta :

Answer:

4820.9 J of work is done on the flight bag.

Explanation:

Given:

Force acting on the bag is, [tex]F=30.0\ N[/tex]

Displacement of the bag caused by the force is, [tex]S=250.0\ m[/tex]

Angle between the direction of force and direction of displacement caused is, [tex]\theta = 50\°[/tex]

Now, the formula to calculate work done on a body by a force 'F' causing displacement 'S' at an angle [tex]\theta[/tex] between the two vectors is given as:

[tex]W=FS\cos \theta[/tex]

Plug in the given values and solve for work done 'W'. This gives,

[tex]W=(30.0\ N)(250.0\ m)(\cos 50)\\W=4820.9 \textrm{ N-m or 4820.9 J}[/tex]

Therefore, the work done on the flight bag is 4820.9 J.

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