In​ 2000, the population of a country was approximately 5.77 million and by 2077 it is projected to grow to 13 million. Use the exponential growth model [tex]l_A = A_oe^{kt}[/tex]​, in which t is the number of years after 2000 and [tex]A_0[/tex] is in​ millions, to find an exponential growth function that models the data.
In which year will Israel's population be 12 million?

Respuesta :

Answer:

Part 1 : [tex]I_A = 5.77 e^{0.01055t}[/tex]

Part 2 : In 2069 the population would be 12 millions.

Step-by-step explanation:

Part 1 : Given function that shows the population( in millions ) of Israel after t years since 2000,

[tex]I_A = A_0 e^{kt}[/tex]

If t = 0,

[tex]I_A = 5.77[/tex]

[tex]\implies 5.77 = A_0 e^{0}\implies A_0 = 5.77[/tex]

If t = 77 years,

The population in 2077,

[tex]I_A = A_0 e^{77k}=5.77 e^{77k}[/tex]

According to the question,

Population in 2077 = 13 millions

[tex]13 = 5.77 e^{77k}[/tex]

[tex]\frac{13}{5.77} = e^{77k}[/tex]

Taking ln both sides,

[tex]\ln(\frac{13}{5.77}) = \ln(e^{77k})[/tex]

[tex]\ln(\frac{13}{5.77}) = 77k[/tex]

[tex]\implies k = 0.010549\approx 0.01055[/tex]

Hence, the required function would be,

[tex]I_A = 5.77 e^{0.01055t}[/tex]

Part 2 : If [tex]I_A = 12[/tex]

[tex]12 = 5.77 e^{0.01055t}[/tex]

[tex]\frac{12}{5.77} = e^{0.01055t}[/tex]

Taking ln both sides,

[tex]\ln(\frac{12}{5.77}) = \ln(e^{0.01055t})[/tex]

[tex]\ln(\frac{12}{5.77}) =0.01055t[/tex]

[tex]\implies t\approx 69[/tex]

∵ 2000 + 69 = 2069

Hence, in 2069 the population would be 12 millions.

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