Question

Gas Laws
The absolute temperature of a gas is increased four times while maintaining a constant volume. What happens to the pressure
of the gas?

Answer 1

Answer:

The pressure of the gas increases by the four times.

Explanation:

According to the Gay-Lussac's law

The relationship between pressure and temperature is as follows.

$\frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}$\

From the given data, we considered 1 is a initial temperature and 4 is final  temperature. Initial pressure is considered as $P_{1}$.

Let's find the final pressure of the gas.

$P_{2}=\frac{P_{1}T_{2}}{T_{1}}$

Substitute the temperature value.

$P_{2}=\frac{P_{1}(4)}{1}$

$P_{2}=4P_{1}$

Therefore, The pressure of the gas increases by the four times.