Answer:
It is going to be bell-shaped(normally distributed), with mean [tex]\mu = 24[/tex] and standard deviation [tex]s = \frac{2}{\sqrt{15}} = 0.5164[/tex].
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], a large sample size can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\frac{\sigma}{\sqrt{n}}[/tex].
What can we say about the shape of the distribution of the sample mean time?
It is going to be bell-shaped(normally distributed), with mean [tex]\mu = 24[/tex] and standard deviation [tex]s = \frac{2}{\sqrt{15}} = 0.5164[/tex].
