Question

During a radio contest, $50 is added to the prize money each time a caller answers the contest question incorrectly. The first
caller has a chance to win $100. Which equation represents the amount the 10th caller receives if this caller is the first to
answer the question correctly?
a10=100+(10-1)50
a10=50+(10-1)100
a11=100+(11-1)50
a11=50+(11-1)100

Answer 1

Answer:

The expression is  $a_{10}$ = 100+(10 - 1)50 .

Step-by-step explanation:

Given as :

The amount of money added as prize money =  $50

The amount that first caller will win =  $a_{1}$ = $100

Let The amount that 10th caller win = $A

∴ common difference for the callers amount = $50

Now, According to question

The given statement is in arithmetic expression

So, For A.P , The nth term is written as

nth term = first term  + (n - 1) × common difference

I.e $a_{10}$ = $a_{1}$ +  (n - 1) × common difference

Here n = 10

Or, A = $100 +  (10 - 1) × 50

So, The expression =  $a_{10}$ = 100+(10 - 1)50

Hence, The expression is  $a_{10}$ = 100+(10 - 1)50 . Answer

Answer 2

Answer:

The answer is A.

Step-by-step explanation:

a10=100+(10-1)50

Got it correct in the quiz.