Respuesta :

Answer:

16, 20, 24, 28, and 32

Step-by-step explanation:

Given:

The [tex]n^{th}[/tex] term of the sequence is given as:

[tex]a_n=a_{n-1}+4[/tex]

The first term is given as [tex]a_1=16[/tex]

We need to find the remaining 4 terms.

So, we plug in 2, 3, 4, 5 for 'n' and find the remaining 4 terms of the sequence.

For [tex]n=2[/tex]

[tex]a_2=a_{2-1}+4\\\\a_2=a_1+4\\\\a_2=16+4=20[/tex]

For [tex]n=3[/tex]

[tex]a_3=a_{3-1}+4\\\\a_3=a_2+4\\\\a_3=20+4=24[/tex]

For [tex]n=4[/tex]

[tex]a_4=a_{4-1}+4\\\\a_4=a_3+4\\\\a_4=24+4=28[/tex]

For [tex]n=5[/tex]

[tex]a_5=a_{5-1}+4\\\\a_5=a_4+4\\\\a_5=28+4=32[/tex]

Therefore, the first five terms of the given sequence are:

16, 20, 24, 28, and 32

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