Question

-
69. A 1 mol sample of gas has a temp of 225K, a vol of 3.3L, and a pressure of 2000 torr
What would be the temperature if the amount of
stant while pressure
drops to 900 torr and volume to 2.75L?
2
co
20
s
C

Answer 1

Answer:

T₂  = 84.375 K

Explanation:

Given data:

Initial volume = 3.3 L

Initial pressure = 2000 torr

Initial temperature = 225 K

Final temperature = ?

Final volume = 2.75 L

Final pressure = 900 torr

Formula:

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂  

T₂  = P₂V₂ T₁ /P₁V₁

T₂  = 900 torr× 2.75 L× 225 K / 2000 torr×3.3 L

T₂  = 556875 K/ 6600

T₂  = 84.375 K