The drawing shows three identical springs hanging from the ceiling. Nothing is attached to the first spring, whereas a 4.5 n block hangs from the second spring. A block of unknown weight hangs from the third spring. From the drawing, determine

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<Continuation of the question>

(a) the spring constant (in N/m) and

(b) the weight of the block hanging from the third spring.

the distance for the first spring is 20cm, the second 35cm, the third 50cm.

Answer:

a) To find the spring constant, we'll use the formula

F=kx, if we make k the subject we'll get

k=F/x, where F=4.5N, x = 35cm - 20cm = 15cm = 0.15m

k=F/x = 4.5N/0.15m =  30N/m is the Answer

b) to find the weight of block hanging on third spring

we use the formula F=kx

where k = 30N/m, x=50cm-20cm=30cm=0.30m

F=kx = (30N/m)*(0.30m) = 9N  is the Answer

The spring constant and the weight hanging on the third spring are respectively; k = 30 N/m and F = 9N

What is the spring constant?

A) Formula for force in a spring is;

F = kx

where;

k is spring constant

x is displacement

we are given;

F = 4.5N

x = 35cm - 20cm = 15cm = 0.15m

Thus;

k = F/x = 4.5/0.15

k = 30N/m

B) To get the weight of block hanging on third spring, we will use the formula; F=kx

where;

k = 30N/m

x = 50 cm - 20 cm = 30cm = 0.30m

Thus;

F = 30N/m × 0.30m

F = 9N  

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