Question

Write the electron configuration for the monatomic ions formed ions formed from the following elements (which form the greatest concentration of monatomic ions in seawater):
(a) Cl
(b) Na
(c)Mg
(d) Ca

Answer 1

Answer:

(a) $Cl^{-}-1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}$

(b) $Na^{+}-1s^{2}2s^{2}2p^{6}$

(c) $Mg^{2+}-1s^{2}2s^{2}2p^{6}$

(d) $Ca^{2+}-1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}$

Explanation:

Electronic configuration of an element is the short representation in an atom.The chemical properties are based on these electron arrangement.

(a)

The given element is chlorine.

Atomic number of chlorine is 17. To form the monoatomic ion it gains one electron. The electronic configuration of the chloride ion is as follows.

$Cl^{-}-1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}$

(b)

The given element is sodium.

Atomic number of sodium  is 11. To form the monoatomic ion it loose one electron. The electronic configuration of the sodium ion is as follows.

$Na^{+}-1s^{2}2s^{2}2p^{6}$

(c)

The given element is Magnesium.

Atomic number of magnesium  is 12. To form the monoatomic ion it loose two electrons. The electronic configuration of the magnesium ion is as follows.

$Mg^{2+}-1s^{2}2s^{2}2p^{6}$

(d)

The given element is Calcium.

Atomic number of calcium  is 20. To form the monoatomic ion it loose two electrons. The electronic configuration of the calcium ion is as follows.

$Ca^{2+}-1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}$