Question

Given the following system of equations:

−4x + 8y = 16
2x + 4y = 8

What action was completed to create this new equivalent system of equations?

−2x + 4y = 8
2x + 4y = 8

(A) Multiply the second equation, 2x + 4y = 8, by −1.
(B) Multiply the first equation, −4x + 8y = 16, by −1.
(C) Divide the second equation, 2x + 4y = 8, by 2.
(D) Divide the first equation, −4x + 8y = 16, by 2.v

Answer 1

Answer:

(D) Divide the first equation, $-4x + 8y = 16$ , by 2.

Step-by-step explanation:

Given:

$-4x + 8y = 16 \ \ \ \ equation \ 1$

$2x + 4y = 8 \ \ \ \ equation \ 2$

We need to find the operation performed on equation so as to get resultant equation as:

$-2x + 4y = 8$

$2x + 4y = 8$

From Above we can see that there is no change in equation 2 with respect to resultant equation.

Also Resultant equation is simplified form of equation 1.

Simplifying equation 1 we get;

$-4x + 8y = 16$

We can see that 2 is the common multiple on both side.

Hence we will divide equation 1 with 2 we get

$\frac{-4x}{2}+\frac{8y}{2}=\frac{16}{2}\\\\-2x+4y=8$

which is the resultant equation.

Hence (D) Divide the first equation, $-4x + 8y = 16$ , by 2 is the correct option.

Answer 2

Answer:

d, or divide the first equation.

Step-by-step explanation: