Question

Molly is making strawberry-infused water. For each ounce of strawberry juice, she uses 3 time many ounces of water. She wants to make a total of 64 ounces of strawberry infused water. If we let s represent the amount of strawberry juice she needs to use and let w represent the amount of water she will use, then which of the following systems of equations models this situation?

Answer 1

Answer:

Molly needs 48 ounces of water and 16 ounces of strawberries.

Step-by-step explanation:

Givens

• For each ounce of strawberry juice, she uses 3 times many ounces of water.
• She wants to make a total of 64 ounces of strawberry infused water, that menas, 64 ounces between fruit and water.

If $s$ represents strawberry and $w$ represents water, the equations would be

$w=3s$

$s+w=64$

This system representes the given situation, because the total ounces of water is three times the ounces of strawberry juice. And the sum between those two is 64 ounces.

So, we replace the first equation into the second one to solve

$s+w=64\\s+3s=64\\4s=64\\s=\frac{64}{4}\\ s=16$

Then, we replace this value in the other equation, to find the missing variable

$w=3s\\w=3(16)\\w=48$

Therefore, Molly needs 48 ounces of water and 16 ounces of strawberries.

Answer 2

A system of equations is a set of related equation.

The system of equations is:$\mathbf{s = 3w}$ and $\mathbf{s +w = 64}$

The given parameters are:

$\mathbf{s \to strawberry}$

$\mathbf{w \to water}$

She makes 3 times as many ounces of water means that:

$\mathbf{s = 3w}$

She needs a total of 64 ounces.

This means that:

$\mathbf{s +w = 64}$

Hence, the system of equations is:

$\mathbf{s = 3w}$

$\mathbf{s +w = 64}$

Read more about system of equations at:

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