Question

What is logx+logy−2logz written as a single logarithm?
plss help!

Answer 1

Answer:

log ($\frac{xy}{z^2}$)

Step-by-step explanation:

Using the rules of logarithms

• log$x^{n}$ ⇔ n log x

• log x + log y = log(xy)

• log x - log y = log ($\frac{x}{y}$)

Given

log x + log y - 2 log z

= log(xy) - log z²

= log ($\frac{xy}{z^2}$)

Answer 2

The expression written as a single logarithm is log(xy/z²)

Using the laws of logarithm as shown:

loga - log b = log(a/b)

loga + log b = log(ab)

Given the expression

logx+logy−2logz

= log(xy) - 2 logz

= log(xy) - logz²

= log(xy/z²)

Hence the expression written as a single logarithm is log(xy/z²)

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