Answer:
1737.8 N
Explanation:
Given information
[tex]F_1= 821 N[/tex]
[tex]F_2= 1140 N[/tex]
[tex]\theta_1=32^{\circ}[/tex]
[tex]\theta_2=26^{\circ}[/tex]
Net force, [tex]F_{net}=F_1 cos \theta_1+F_2 cos \theta_2=821cos 32^{\circ}+ 1140 cos 26^{\circ}=1737.833662 N \approx 1737.8 N[/tex]