Question

A woman of mass 44 kg jumps off the bow of
a 49 kg canoe that is intially at rest.
If her velocity is 2.5 m/s to the right, what
is the velocity of the canoe after she jumps?
Answer in units of m/sˆı.

Answer 1

Answer:

2.2 m/s to the left

Explanation:

Momentum is conserved, so:

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

0 = (44 kg) (2.5 m/s) + (49 kg) v

v = -2.2 m/s