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A rectangle has a height of 3b^2 and a width of 4b^4+2b-6.

Express the area of the entire rectangle.

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Answer:

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Step-by-step explanation:

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The area of the rectangle will be 12b⁶ + 6b³ – 18b².

What is the area of the rectangle?

Let H be the height and W be the width of the rectangle. The area of the rectangle is the product of height and width.

Then the area of the rectangle will be

Area of the rectangle = H × W square units

A rectangle has a height of 3b² and a width of 4b⁴ + 2b – 6.

Then the area of the rectangle will be

Substitute H = 3b² and W = 4b⁴ + 2b – 6. Then the area of the rectangle will be

Area of the rectangle = 3b² x (4b⁴ + 2b – 6)

Simplify the equation, we have

Area of the rectangle = 3b² · 4b⁴ + 3b² · 2b – 3b² · 6

Area of the rectangle = 12b⁶ + 6b³ – 18b²

Thus, the area of the rectangle will be 12b⁶ + 6b³ – 18b².

More about the area of the rectangle link is given below.

https://brainly.com/question/20693059

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