Ms. Johnson uses a statistics program to analyze all the data collected by her students during a lab experiment about acceleration due to gravity. The program reports =31.5 and . What is the variance of the data? Round to the nearest tenth. 1.6 2.5 5.6 6.3

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Answer:

The Variance will be 6.3.

Step-by-step explanation:

Note: You probably unintentionally missed to mention the standard deviation in your question. After a little research, it seem that standard deviation is 2.5 in your question that you should have mentioned in your question. Anyways, I am assuming the standard deviation as 2.5, and based on this, answering your question. It anyways will clear your concept, hopefully.  

The complete version of Question:

Ms. Johnson uses a statistics program to analyze all the data collected by her students during a lab experiment about the acceleration due to gravity. The program reports a mean of 31.5 and a standard deviation of 2.5.

What is the variance of the data? Round to the nearest tenth.

1.6  2.5  5.6  6.3

Solution:

As the standard deviation = σ = 2.5

As the know that Standard deviation (σ) is equal to the square root of the variance.

σ = [tex]\sqrt{v}[/tex]

Just take square of the standard deviation to get the variance.

(2.5)² = [tex](\sqrt{v})^{2}[/tex]

v = 6.25 ⇒ v = 6.3  

Hence. the Variance will be 6.3.

Keywords:  Variance, standard deviation

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Answer:

6.3 or answer D

Step-by-step explanation:

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