Question

given that the nth term Tn of a sequence is Tn=2n+5 find
the 5th term
the 8th term
the lowest common multiple of the 5ht and the 8th term
of the sequence

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Answer 1

Answer:

The lowest common multiple of the 5th term  and the 8th term of the sequence is 3

Step-by-step explanation:

Given that the nth term Tn of a sequence is $Tn=2n+5\hfill(1)$

To find the 5th terms of the sequence

put n=5 in (1) we get

$T_5=2(5)+5$

$T_5=10+5$

$T_5=15$

The lowest common multiple of 5th term of the sequences are 3 and 5

To find the 8th terms of the sequence

put n=8 in (1) we get

$T_8=2(8)+5$

$T_8=16+5$

$T_8=21$

The lowest common multiple of 8th term  of the sequence are 3 and 7

Therefore the lowest common multiple of 5th and 8th term of the sequence is 3