Answer:
The speaker should be placed at either 4.111 m or 7.888 m
Explanation:
We have given frequency f = 90 Hz
and velocity of the sound v = 340 m /sec
So wavelength [tex]\lambda =\frac{v}{f}=\frac{340}{90}=3.777m[/tex]
Here path difference will be equal to wavelength
So [tex]s_1-s_2=\pm \frac{\lambda }{2}=\pm \frac{3.777}{2}=\pm 1.888[/tex]
[tex]s_1-6=\pm 1.888[/tex]
[tex]s_1=4.111m,\ 7.888m[/tex]
So the speaker should be placed at either 4.111 m or 7.888 m