Question

I know that the balloon weighs about 210 kg. The balloon itself weighs 7/9 out of this. The rest of the weight is composed of sand sacks and empty gas tanks. If the weight of the gas tank is 1/6 of that of the sacks, how much do the tanks and the sacks weigh each?

Answer 1

Answer:

Gas Tanks weighs 20/3kg i.e. 6.67kg while Sacks weighs 40kg

Step-by-step explanation:

Total weight = 210kg

$Balloon Weight = \frac{7}{9} *210\\Balloon Weight = \frac{490}{3}kg$

Balloon Weight = 163.33kg

Remaining Weight = 210 - (490/3)

$=\frac{630-490}{3}$

=46.67kg

Let the weight of Gas tank = g

Let the weight of Sacks = s

This remaining weight comprises of weight of Sacks and Gas Tanks.

i.e.

g+s = 140/3 = 46.67

As given that,

$g=\frac{1}{6}*s$

So,

$s(\frac{1}{6}+1) = \frac{140}{3}$

$s(\frac{7}{6} ) = \frac{140}{7}$

s=40kg

As provided

Now to find g:

g+s = 140/3

$g=\frac{140}{3}-s\\=\frac{140}{3} -40\\=\frac{20}{3}kg\\=6.67kg$