Answer:
The value of [tex]\frac{f}{g} (x)[/tex] is [tex]\dfrac{4x + 1}{x^{2} -5 }[/tex]
Step-by-step explanation:
Given as :
f(x) = 4 x + 1
g(x) = x² - 5
Let the value of [tex]\frac{f}{g} (x)[/tex] = A
So, According to question
[tex]\frac{f}{g} (x)[/tex] = [tex]\dfrac{f(x)}{g(x)}[/tex]
Or, A = [tex]\dfrac{4x + 1}{x^{2} -5 }[/tex]
So, The value of [tex]\frac{f}{g} (x)[/tex] = A = [tex]\dfrac{4x + 1}{x^{2} -5 }[/tex]
Hence, The value of [tex]\frac{f}{g} (x)[/tex] is [tex]\dfrac{4x + 1}{x^{2} -5 }[/tex] Answer