Question

The ozonization of pentene in carbon tetrachloride solution at 25 o C5H10 + O3 C5H10O3 is first order in C5H10 and first order in O3.

1.Complete the rate law for this reaction in the box below.
Use the form k[A]m[B]n... , where '1' is understood for m, n ...(don't enter 1) and concentrations taken to the zero power do not appear.

Rate =

2.In an experiment to determine the rate law, the rate of the reaction was determined to be 649 Ms-1 when [C5H10] = 0.128 M and [O3] = 4.41E-2 M. From this experiment, the rate constant is ______M-1s-1.

Answer 1

Answer:

1. Rate = k [C₅H₁₀] [O₃]

2. k = 1.15 × 10⁵ M⁻¹s⁻¹

Explanation:

Let's consider the following reaction.

C₅H₁₀ + O₃ → C₅H₁₀O₃

The order of reaction for C₅H₁₀ is 1 and the order of reaction for O₃ is 1 as well.

The rate law is:

Rate = k [C₅H₁₀] [O₃]

where,

k is the rate constant

2. In an experiment, the rate is 649 M/s,[C₅H₁₀] = 0.128 M and [O₃] = 4.41 × 10⁻² M.

Rate = k [C₅H₁₀] [O₃]

649 M/s = k (0.128 M) (4.41 × 10⁻² M)

k = 1.15 × 10⁵ M⁻¹s⁻¹