Answer:
The net force acting on the body, F = 11 N
Explanation:
Given data,
The force acting on the body, f = 5 N
Another force acting on the body, f' = 6 N
The direction of both forces is in the same direction.
The net force is given by the resultant vector,
[tex]F= \sqrt{f^{2} + f'^{2} + 2 ff' Cos \theta}[/tex]
[tex]F= \sqrt{f^{2} + f'^{2} + 2 ff'[/tex] (∵ θ = 0)
[tex]F=\sqrt{(f + f')^{2} }[/tex]
F = f + f'
= 5 N + 6 N
= 11 N
Hence, the net force acting on the body, F = 11 N