Question

A snowboard has a mass of 1.53 kg. What is the static frictional force on the snowboard if the
waxed snowboard was lying horizontally on a wet & snowy surface (u s = 0.2)?

Answer 1

Answer:

Static friction, F=2.9988 N

Explanation:

Static Friction: It is the friction between two or more solid body that are not moving relative to each other.

              When an external force is applied to a body that is in contact with another body, static friction opposes the applied force upto a certain limit, keeping the body at rest. When the applied force exceeds the certain limit the  body begins to move. At that moment applied force is equal to limiting value of  static friction F.

                It varies linearly with normal force(N)

                       F∝N

                         F=μN   (where μ is constant of proportionality and known as coefficient of static friction)

Now,

Mass, m=1.53 kg

Coefficient of static friction, μ=0.2

Normal force, N=m×g

                        =$1.53\times9.8$     (g=9.8 m/s²)

                         =14.994 N  

Static friction, F= μN  

                         =$0.2\times14.994$

                          = 2.9988 N