Answer:
The required points of the given line segment are ( - 3, - 7 ).
Step-by-step explanation:
Given that the line segment CD whose midpoint M is ( 1, - 1 ) and point D is ( 5, 5 ), then we have to find point C of the line segment CD-
As we know that-
If a line segment AB is with endpoints ([tex]x_{1}, y_{1}[/tex] ) and ([tex]x_{2}, y_{2}[/tex] then the mid points C are-
C = ( [tex]\frac{ x_{1} + x_{2} }{2}[/tex] , [tex]\frac{ y_{1} + y_{2} }{2}[/tex] )
Here,
Let C ( x, y ), D ( 5, 5 ) with midpoint M ( 1, -1 )-
then by the midpoint formula-
( 1, -1 ) = ( [tex]\frac{x+ 5}{2}[/tex] , [tex]\frac{y + 5}{2}[/tex]
On comparing x coordinate and y coordinate -
We get,
( [tex]\frac{x+ 5}{2}[/tex] = 1 , [tex]\frac{y + 5}{2}[/tex] = -1 )
( x + 5 = 2, y + 5 = - 2 )
( x = 2 - 5, y = -2 - 5 )
( x = - 3, y = -7 )
Hence the required points C are (- 3, - 7 ).
We can also verify by putting these points into Midpoint formula.