Question

You set out to reproduce Thomson’s e/m experiment with an accelerating potential of 150 V and adeflecting electric field of magnitude 6.0 ×106 N/C(a) At what fraction of the speed of light do the electrons move?(b) What magnetic-field magnitude will yield zero beam deflection?(c) With this magnetic field, how will the electron beam behave if you increase the acceleratingpotential above 150 V?

Answer 1

Answer:

a. v' = 24.22 x 10 ⁻³

b. β = 0.825 T

Explanation:

V = 150 V , E = 6.0 x 10 ⁶ N / C

a.

¹/₂ * m * v² = e * V

v = √ 2 * e / m * V

v = √ 2 * 1.76 x 10 ¹¹ * 150 v  = √ 5.28 x 10 ¹³

v = 7.26 x 10 ⁶ m /s

v' / c = 7.26 x 10 ⁶ m /s  / 3.0 x 10 ⁸ = 24.22 x 10 ⁻³

b.  

β = E / V

β = 6.0 x 10 ⁶ / 7.266 x 10 ⁶

β = 0.825 T

c.

When the increasing the accelerating potential speed it doesn't change the up wired the electric force and the magnetic force the electron be beat down more .