The question is missing the figure. So, the figure is attached below.
Answer:
The area of the base of the pyramid is 36 square inches.
Step-by-step explanation:
Given:
Volume of the pyramid is, [tex]V=108\ in^3[/tex]
The height of the pyramid is, [tex]h=9\ in[/tex]
Let the area of the base be 'A'.
So, the volume of the pyramid is given as:
[tex]V=\frac{1}{3}Ah[/tex]
Rewrite the given formula in terms of 'A'. This gives,
[tex]A=\frac{3V}{h}[/tex]
Now, plug in 108 for 'V', 9 for 'h' and solve for 'A'. This gives,
[tex]A=\frac{3\times 108}{9}\\\\A=3\times 12\\\\A=36\ in^2[/tex]
Therefore, the area of the base of the pyramid is 36 square inches.
