Question

Benjamin​ & Associates, a real estate​ developer, recently built 195 condominiums in​ McCall, Idaho. The condos were either two​-bedroom units or three​-bedroom units. If the total number of bedrooms in the entire complex is 497​, how many two​-bedroom units are​ there? How many three​-bedroom units are​ there?

Answer 1

Answer:

There are 88 two bedroom units and 107 three bedroom units.

Step-by-step explanation:

Consider the provided information.

Let x is the number of two-bedroom units and y is the number of three-bedroom units.

Real estate​ developer, built 195 condominiums in​ McCall, Idaho.

$x+y=195$

$x=195-y$

The total number of bedrooms in the entire complex is 497​.

$2x+3y=497$

Substitute the value of x in above equation.

$2(195-y)+3y=497$

$390-2y+3y=497$

$y=497-390$

$y=107$

Substitute y = 107 in $x=195-y$.

$x=195-107$

$x=88$

Hence, there are 88 two bedroom units and 107 three bedroom units.