Answer:
Therefore,
[tex](m^{2}+2mn+ n^{2}+5)+(2m^{2}-3n^{2}-2)+(-3mn+2n^{2} +m-3)=3m^{2}-mn+m[/tex]
Step-by-step explanation:
Given:
[tex](m^{2}+2mn+ n^{2}+5)+(2m^{2}-3n^{2}-2)+(-3mn+2n^{2} +m-3)[/tex]
Addition in Column form is as follow
m² + 2mn + n² + 0m + 5
+ 2m² + 0mn - 3n² + 0m - 2
+ 0m² - 3mn + 2n² + m - 3
3m² - mn + 0n² + m+ 0
Therefore,
[tex](m^{2}+2mn+ n^{2}+5)+(2m^{2}-3n^{2}-2)+(-3mn+2n^{2} +m-3)=3m^{2}-mn+m[/tex]
