A collection of 33 coins having dimes quarters and nickels, there are 3 times more nickels then dimes and half the amount of dimes as nickels, all of the coins equal $3.30 how many of each coin?

Respuesta :

Answer:

Each coins are quarters of 6, nickels of 18 and the dimes of 9.

Step-by-step explanation:

There is a mistake in question.

The question must be:

A collection of 33 coins having dimes quarters and nickels, there are 3 times as many nickels as quarters, and one-half as many dimes as nickels, all of the coins equal $3.30 how many coins of each kind are there?

Now, to find the number coins of each.

Let the quarters be [tex]x[/tex].

Nickels be [tex]3x[/tex].

And the dimes be [tex]\frac{3x}{2}[/tex].

So, the total collection of coins are:

[tex]x+3x+\frac{3x}{2} =33.[/tex]

On adding the fractions we get:

[tex]\frac{2x+6x+3x}{2} =33[/tex]

[tex]\frac{11x}{2} =33[/tex]

Multiplying both sides by 2 we get:

[tex]11x=66[/tex]

Dividing both sides by 11 we get:

[tex]x=6.[/tex]

Thus, quarters = 6.

Nickels = [tex]3x=3\times 6=18.[/tex]

Dimes = [tex]\frac{3x}{2} =\frac{3\times 6}{2} =\frac{18}{2}=9 .[/tex]

Therefore, each coins are quarters of 6, nickels of 18 and the dimes of 9.