Answer:
Each coins are quarters of 6, nickels of 18 and the dimes of 9.
Step-by-step explanation:
There is a mistake in question.
The question must be:
A collection of 33 coins having dimes quarters and nickels, there are 3 times as many nickels as quarters, and one-half as many dimes as nickels, all of the coins equal $3.30 how many coins of each kind are there?
Now, to find the number coins of each.
Let the quarters be [tex]x[/tex].
Nickels be [tex]3x[/tex].
And the dimes be [tex]\frac{3x}{2}[/tex].
So, the total collection of coins are:
[tex]x+3x+\frac{3x}{2} =33.[/tex]
On adding the fractions we get:
[tex]\frac{2x+6x+3x}{2} =33[/tex]
[tex]\frac{11x}{2} =33[/tex]
Multiplying both sides by 2 we get:
[tex]11x=66[/tex]
Dividing both sides by 11 we get:
[tex]x=6.[/tex]
Thus, quarters = 6.
Nickels = [tex]3x=3\times 6=18.[/tex]
Dimes = [tex]\frac{3x}{2} =\frac{3\times 6}{2} =\frac{18}{2}=9 .[/tex]
Therefore, each coins are quarters of 6, nickels of 18 and the dimes of 9.