Answer:
V₂ = 3 L
Explanation:
Given data:
Initial volume = 6.8 L
Initial pressure = 1250 mmHg (1250/760 =1.64 atm)
Initial temperature = 750°C (750 +273 = 1023 K)
Final temperature = 273 K
Final volume = ?
Final pressure = 1 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1.64 atm × 6.8 L × 273 K / 1023 K × 1 atm
V₂ = 3044.5 atm .L. K / 1023 K. atm
V₂ = 3 L
