Question

Eugene had 3 pies. He gave 1 4/5 to his friend. And kept the rest for himself. Who had more pie? How much more?

Answer 1

Answer:

Eugene friend will have more pie than Eugene.

Eugene friend has $\frac{3}{5}$ more pie than Eugene.

Step-by-step explanation:

Given:

Amount of pie Eugene has = 3

Amount of Pie given to friend  = $1\frac{4}{5}$

$1\frac{4}{5}$ can be Rewritten as $\frac{9}{5}$

We need to find who has pie and how much more.

We will first find the amount of pie Eugene is left with.

The amount of pie Eugene is left with is equal to Amount of pie Eugene had minus Amount of pie given to friend.

Framing the equation we get;

The amount of pie Eugene is left = $3-\frac{9}{5}$

We will take LCM to solve the same.

The amount of pie Eugene is left = $3-\frac{9}{5} = \frac{3\times5}{5}-\frac{9}{5} =\frac{15}{5}-\frac{9}{5} = \frac{15-9}{5} =\frac{6}{5}$

Now  $\frac{9}{5} = 1.8$ and  $\frac{6}{5} = 1.2$

Hence  $\frac{9}{5}$ is greater than  $\frac{6}{5}$

Hence Eugene friend will have more pie than Eugene.

Now we will find amount more pie Eugene friend has.

Amount More Eugene friend has can be calculate by Subtracting Amount of of Eugene has with Amount of pie his friend has.

Amount More Eugene friend has =$\frac{9}{5} - \frac{6}{5} =\frac{9-6}{5}= \frac{3}{5}$

Hence Eugene friend has $\frac{3}{5}$ more pie than Eugene.