Respuesta :
Answer:
There will be 15.05 Joules of heat released.
Explanation:
Step 1: Data given
Mass of mercury = 5.00 grams
The specific heat of mercury = 0.14 J/g*K = 0.14 J/g°C
Raise of temperature from 15.0°C to 36.5 °C
Step 2: Calculate heat released
q = m*c*ΔT
⇒ with q = The heat released in Joules
⇒ with m = the mass of mercury = 5.00 grams
⇒ with c = The specific heat of mercury = 0.14 J/g°C
⇒ with ΔT = The change of temperature = T2 - T1 = 36.5°C - 15.0°C = 21.5 °C
q = 5.00g * 0.14 J/g°C * 21.5 °C = 15.05 J
There will be 15.05 Joules of heat released.
The quantity of heat needed to raise 5g of mercury from 15.0°C to 36.5°C is 15.05 Joules
Specific heat Capacity
Given Data
- Specific heat capacity of liquid mercury = 0.14 J/gK.
- Mass = 5.00 g
- T1 = 15.0°C
- T2 = 36.5°C
We know that the expression for the amount of heat is given as
Q =. mcΔT
Substituting our given data into the expression we have
Q = 5*0.14*(36.5 - 15)
Q = 0.7*21.5
Q = 15.05 Joules
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