Answer:
+6
Explanation:
We are given;
We are required to determine the oxidation number of S in the compound.
We need to know that;
Therefore; assuming oxidation number of S is x
Then, (1× 2) + (1 × x) + ( 4 ×(-2)) = 0
2 + x - 8 = 0
x = 6 or +6
Thus oxidation number of Sulfur in BaSO₄ is +6.