Question

A student placed 11.0 g of glucose (C6H12O6 ) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100. mL mark on the neck of the flask was reached.

The flask was then shaken until the solution was uniform. A 55.0 mL sample of this glucose solution was diluted to 0.500 L .

How many grams of glucose are in 100. mL of the final solution?

Answer 1

Answer:

We have 12.1 grams of glucose in 100 mL of solution

Explanation:

Step 1: Data given

Mass of glucose = 11.0 grams

Volume = 100 mL

A 55.0 mL sample of this glucose solution was diluted to 0.500 L .

Step 2: Calculate concentration of glucose

Initially, amount of glucose available in 100 ml of the solution = 11.0 grams

Concentration of glucose = mass/ volume

Concentration=11.0 /0.100

= 110 g/L

We take away, 0.055 L of that solution, creating another solution with it but with 0.500 L of volume

Step 3: calculate concentration of the new volume

⇒ with C1 = Concentration of the first solution

⇒ with V1 = Volume of the first solution

⇒ with C2 = Concentration of the second solution 

⇒ with V2 = Volume of the second solution

C1V1= C2V2

110 * 0.055= C2 * 0.500

= 12.1 g/L -= the concentration of the new solution

Step 4: Calculate the mass in 0.100 L

Concentration = mass/ volume

12.1 = mass/0.100

=1.21 grams

We have 12.1 grams of glucose in 100 mL of solution