Answer:
d. It is at most 25 percent.
Step-by-step explanation:
According to Chebyshev's inequality, for a given number of standard deviations, k, no more than 1/k² can be more than k standard deviations from the mean. In this situation the amount of standard deviations from the mean of the upper and lower bound of salaries are:
[tex]U=\frac{\$92,000-\$80,000}{\$6,000}=2\\L = \frac{\$80,000-\$68,000}{\$6,000}= 2[/tex]
For k = 2, applying Chebyshev's inequality:
[tex]P( \$68,000 \leq X \leq \$92,000)= \frac{1}{2^2} = 0.25[/tex]
Therefore, at most 25% of the salaries are less than $68,000 or more than $92,000.