Answer:
The net force acting on the body is zero, the acceleration acting on the object is also zero.
Explanation:
Let the two equal and opposite forces acts on an object be, f and f'
The net force acting on the object is given by the relation,
The net force is given by the resultant vector,
[tex]F= \sqrt{f^{2} + f'^{2} + 2 ff' Cos \theta}[/tex]
[tex]F= \sqrt{f^{2} - f'^{2} + 2 ff'[/tex] (∵ θ = 180)
[tex]F=\sqrt{(f - f')^{2} }[/tex]
F = f - f'
Since the magnitude of the forces are equal,
F = 0
Hence, the net force acting on the body is zero, the acceleration acting on the object is also zero.