Answer:
If Discriminant,[tex]b^{2} -4ac >0[/tex]
Then it has Two Real Solutions.
Step-by-step explanation:
To Find:
If discriminant (b^2 -4ac>0) how many real solutions
Solution:
Consider a Quadratic Equation in General Form as
[tex]ax^{2} +bx+c=0[/tex]
then,
[tex]b^{2} -4ac[/tex] is called as Discriminant.
So,
If Discriminant,[tex]b^{2} -4ac >0[/tex]
Then it has Two Real Solutions.
If Discriminant,[tex]b^{2} -4ac < 0[/tex]
Then it has Two Imaginary Solutions.
If Discriminant,[tex]b^{2} -4ac=0[/tex]
Then it has Two Equal and Real Solutions.