Respuesta :

Answer:

If Discriminant,[tex]b^{2} -4ac >0[/tex]

Then it has Two Real Solutions.

Step-by-step explanation:

To Find:

If discriminant (b^2 -4ac>0) how many real solutions

Solution:

Consider a Quadratic Equation in General Form as

[tex]ax^{2} +bx+c=0[/tex]

then,

[tex]b^{2} -4ac[/tex] is called as Discriminant.

So,

If Discriminant,[tex]b^{2} -4ac >0[/tex]

Then it has Two Real Solutions.

If Discriminant,[tex]b^{2} -4ac < 0[/tex]

Then it has Two Imaginary Solutions.

If Discriminant,[tex]b^{2} -4ac=0[/tex]

Then it has Two Equal and Real Solutions.

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